# How do you solve 4(r+1)=6-2(1-2r) ?

Aug 31, 2017

The given equation is true for all values of $r$

#### Explanation:

$4 \left(r + 1\right)$
$\textcolor{w h i t e}{\text{XXX}} = 4 r + 4$

$6 - 2 \left(1 - 2 r\right)$
$\textcolor{w h i t e}{\text{XXX}} = 6 - \left(2 - 4 r\right)$

$\textcolor{w h i t e}{\text{XXX}} = 6 - 2 + 4 r$

$\textcolor{w h i t e}{\text{XXX}} = 4 + 4 r$

So if
$\textcolor{w h i t e}{\text{XXX}} 4 \left(r + 1\right) = 6 - 2 \left(1 - 2 r\right)$
then
$\textcolor{w h i t e}{\text{XXX}} 4 r + 4 = 4 + 4 r$

...but this is true for any value of $r$