How do you solve #4/v + 1/5 = 1# and find any extraneous solutions?
1 Answer
Jul 10, 2017
Explanation:
#"subtract " 1/5" from both sides"#
#4/vcancel(+1/5)cancel(-1/5)=1-1/5#
#rArr4/v=4/5#
#"since the fractions are equal and have the same numerator"#
#rArrv=5#
#color(blue)"As a check"#
#"left side "=4/5+1/5=5/5=1=" right side"#
#rArrv=5" is the solution"#
