How do you solve $4 (x - 1) + 3 = 18$ $4(x-1)+3=18$ ?

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Answer 1 · 2017-01-07T14:45:41

See entire solution process below:

First, expand the terms within the parenthesis by multiplying each of the them by the term outside the parenthesis - $4$ $color(red)(4)$ :

$4 (x - 1) + 3 = 18$ $color(red)(4)(x - 1) + 3 = 18$

$(4 \times x) - (4 \times 1) + 3 = 18$ $(color(red)(4) xx x) - (color(red)(4) xx 1) + 3 = 18$

$4 x - 4 + 3 = 18$ $4x - 4 + 3 = 18$

We can now add the constants on the left side of the equation:

$4 x - 1 = 18$ $4x - 1 = 18$

Next, we can add $1$ $color(red)(1)$ to each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$4 x - 1 + 1 = 18 + 1$ $4x - 1 +color(red)(1) = 18 + color(red)(1)$

$4 x - 0 = 19$ $4x - 0 = 19$

$4 x = 19$ $4x = 19$

Now we can divide each side of the equation by $4$ $color(red)(4)$ to solve for $x$ $x$

$\frac{4 x}{4} = \frac{19}{4}$ $(4x)/color(red)(4) = 19/color(red)(4)$

$(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = 19/4$

$x = 19/4$

How do you solve 4(x-1)+3=184(x−1)+3=184(x-1)+3=18?