How do you solve #4( x - 1) \leq - 5( x - 1)#?
1 Answer
Nov 18, 2016
Explanation:
distribute the brackets on both sides of the inequality.
#rArr4x-4<=-5x+5# add 5x to both sides.
#4x+5x-4<=cancel(-5x)cancel(+5x)+5#
#rArr9x-4<=5# add 4 to both sides.
#9xcancel(-4)cancel(+4)<=5+4#
#rArr9x<=9# To solve for x, divide both sides by 9
#(cancel(9) x)/cancel(9)<=9/9#
#rArrx<=1" is the solution"#
