# How do you solve -4(x+2)^2=-20?

$x = - 2 \pm \sqrt{5}$
Divide both sides by -4 to give ${\left(x + 2\right)}^{2} = 5$
Take the square root $\left(x + 2\right) = \pm \sqrt{5}$
Subtract 2 from both sides $x = - 2 \pm \sqrt{5}$