# How do you solve -4(x+2)^2=-20?

$x = - 2 + \sqrt{5}$ and $x = - 2 - \sqrt{5}$

#### Explanation:

From the given:
$- 4 {\left(x + 2\right)}^{2} = - 20$

divide both sides of the equation by $- 4$

$\frac{- 4 {\left(x + 2\right)}^{2}}{- 4} = \frac{- 20}{- 4}$

$\frac{\cancel{- 4} {\left(x + 2\right)}^{2}}{\cancel{- 4}} = \frac{- 20}{- 4}$

${\left(x + 2\right)}^{2} = 5$

Extract the square root of both sides of the equation

$\sqrt{{\left(x + 2\right)}^{2}} = \pm \sqrt{5}$

$\left(x + 2\right) = \pm \sqrt{5}$

$x = - 2 + \sqrt{5}$ and $x = - 2 - \sqrt{5}$

God bless....I hope the explanation is useful.