How do you solve #4(x-2)=5#?

2 Answers
Jun 12, 2017

Answer:

See a solution process below:

Explanation:

Step 1) Divide each side of the equation by #color(red)(4)# to eliminate the need for parenthesis while keeping the equation balanced:

#(4(x - 2))/color(red)(4) = 5/color(red)(4)#

#(color(red)(cancel(color(black)(4)))(x - 2))/cancel(color(red)(4)) = 5/4#

#x - 2 = 5/4#

Step 2) Add #color(red)(2)# to each side of the equation to solve for #x# while keeping the equation balanced:

#x - 2 + color(red)(2) = 5/4 + color(red)(2)#

#x - 0 = 5/4 + (4/4 xx color(red)(2))#

#x = 5/4 + 8/4#

#x = 13/4#

Jun 12, 2017

Answer:

#x = 13/4#

Explanation:

Divide both sides by 4 to get

#x-2 = 5/4#

Add #2# to both sides to get

#x = 5/4 +2#

Calculate and get

#x = 13/4#