# How do you solve 4(x-2)=5?

Jun 12, 2017

See a solution process below:

#### Explanation:

Step 1) Divide each side of the equation by $\textcolor{red}{4}$ to eliminate the need for parenthesis while keeping the equation balanced:

$\frac{4 \left(x - 2\right)}{\textcolor{red}{4}} = \frac{5}{\textcolor{red}{4}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}} \left(x - 2\right)}{\cancel{\textcolor{red}{4}}} = \frac{5}{4}$

$x - 2 = \frac{5}{4}$

Step 2) Add $\textcolor{red}{2}$ to each side of the equation to solve for $x$ while keeping the equation balanced:

$x - 2 + \textcolor{red}{2} = \frac{5}{4} + \textcolor{red}{2}$

$x - 0 = \frac{5}{4} + \left(\frac{4}{4} \times \textcolor{red}{2}\right)$

$x = \frac{5}{4} + \frac{8}{4}$

$x = \frac{13}{4}$

Jun 12, 2017

$x = \frac{13}{4}$

#### Explanation:

Divide both sides by 4 to get

$x - 2 = \frac{5}{4}$

Add $2$ to both sides to get

$x = \frac{5}{4} + 2$

Calculate and get

$x = \frac{13}{4}$