How do you solve #4(x+3)=5(x-2)# for x?

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Answer 1 · 2017-05-03T08:00:13

#4x+12=5x-10# and from here #x=22#

Arrange your equation:

#4x+12=5x-10#

or

#4x-5x=-10-12#

#-x=-22#

or

#x=22#

This is the solution for x.

#x=22#