# How do you solve 40+ 5p = 4( 3p + 1) + 5p?

Sep 10, 2017

Distribute, add like terms, then solve.

#### Explanation:

So you started with

$40 + 5 p = 4 \left(3 p + 1\right) + 5 p$

The first thing you'd do is distribute the $4$ to the $3 p$ and $1$ that are in parentheses, which is just $4 \cdot 3 p$ and $4 \cdot 1$.

Your equation would then look like:

$40 + 5 p = 12 p + 4 + 5 p$

You'd then add like terms, which in this case is $12 p$ and $5 p$ on the right side of the equation, giving you

$40 + 5 p = 17 p + 4$

Then you just have to solve for $p$

$40 + 5 p = 17 p + 4$

$\text{ " -5p" } - 5 p$

$40 = 12 p + 4$

$- 4 \text{ } - 4$

$36 = 12 p$

$\div 12 \text{ } \div 12$

So

$3 = p$