How do you solve $40+ 5p = 4( 3p + 1) + 5p$ ?

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Answer 1 · 2017-09-10T21:10:15

Distribute, add like terms, then solve.

So you started with

$40+5p = 4(3p+1)+5p$

The first thing you'd do is distribute the $4$ to the $3p$ and $1$ that are in parentheses, which is just $4 * 3p$ and $4 * 1$ .

Your equation would then look like:

$40 + 5p = 12p + 4 + 5p$

You'd then add like terms, which in this case is $12p$ and $5p$ on the right side of the equation, giving you

$40 + 5p = 17p +4$

Then you just have to solve for $p$

$40 + 5p = 17p + 4$

$" " -5p" " -5p$

$40 = 12p +4$

$-4" " -4$

$36 = 12p$

$div 12" " div 12$

So

$3= p$

How do you solve 40+ 5p = 4( 3p + 1) + 5p40+ 5p = 4( 3p + 1) + 5p?