How do you solve #4ln3x=15#?

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Answer 1 · 2015-12-01T19:32:50

Use exponentiation to solve ...

#4ln(3x)=15#

#ln3x=15/4=3.75#

Now, exponentiate both sides ...

#e^(ln3x)=e^3.75#

Simplify and solve for x ...

#3x=e^3.75#

#x=(e^3.75)/3~~14.1737#

hope that helped