# How do you solve 4log_4 7?

You can take the $4$ in front of the $\log$ "inside" it as:
${\log}_{4} {\left(7\right)}^{4} =$
${\log}_{4} \left(2401\right) =$
${\log}_{4} \left(2401\right) = \ln \frac{2401}{\ln} \left(4\right) = 5.614$