Question

How do you solve `4n^{2}+16n-16=-7` ?

Answer 1

`1/2 and - 9/2`

Explanation:

I use the new Transforming Method (Socratic, Google Search)
`f(n) = 4n^2 + 16n - 9 = 0`
Transformed equation:
`f'(n) = n^2 + 16n - 36 = 0`
Find 2 real roots of f'(n), knowing the sum (-b = - 16) and the product (ac = - 36). They are: 2 and - 18.
The 2 real roots of f(n) are: `n1 = 2/a = 2/4 = 1/2`, and
`n2 = - 18/a = -18/4 = -9/2`
Answers: `1/2 and - 9/2`