Question

How do you solve `4sin^2 x =1` from pi to 2pi?

Answer 1

Solve `4sin^2 x = 1` `(pi, 2pi)`
Ans: `(7pi)/6 and (11pi)/6`

Explanation:

`sin^2 x = 1/4` --> `sin x = +- 1/2`

Within the interval `(pi, 2pi)`, only the answer `(-1/2)` is accepted.

`sin x = - 1/2` --> `x = (7pi)/6` and `x = (11pi)/6`