Question

How do you solve `4sin^2x-4sinx+1=0`?

Answer 1

`x = pi/6+2kpi, pi=0,pm1,pm2,cdots`

Explanation:

Solving for `sinx`

`4sin^2x-4sinx+1=0`

`sinx = (4pmsqrt(4^2-4^2))/8=1/2`

then

`x = arcsin(1/2)+2kpi, pi=0,pm1,pm2,cdots`

`x = pi/6+2kpi, pi=0,pm1,pm2,cdots`