# How do you solve 4t + 1/3 = t + 5/6 + t - 3/6?

##### 1 Answer
Apr 15, 2016

$t = 0$

#### Explanation:

$\textcolor{b l u e}{4 t} + \frac{1}{3} = \textcolor{b l u e}{t} + \frac{5}{6} + \textcolor{b l u e}{t} - \frac{3}{6}$

$\textcolor{b l u e}{4 t - t - t} = \frac{5}{6} - \frac{3}{6} - \frac{1}{3}$

$\textcolor{b l u e}{4 t - 2 t} = \frac{5}{6} - \frac{3}{6} - \frac{1}{3}$

$2 t = \frac{5}{6} - \frac{3}{6} - \frac{1}{3}$

The L.C.M of the denominators ( 6 ,6  and 3) of the L.H.S $= 6$

$2 t = \frac{5}{6} - \frac{3}{6} - \frac{1 \cdot 2}{3 \cdot 2}$

$2 t = \frac{5}{6} - \frac{3}{6} - \frac{2}{6}$

$2 t = \frac{5 - 3 - 2}{6}$

$2 t = \frac{5 - 5}{6}$

$2 t = \frac{0}{6}$

$2 t = 0$

$t = \frac{0}{2}$

$t = 0$