How do you solve #4t-5=14#?

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Answer 1 · 2017-06-29T01:48:11

See a solution process below:

Step 1) Add #color(red)(5)# to each side of the equation to isolate the #t# term while keeping the equation balanced:

#4t - 5 + color(red)(5) = 14 + color(red)(5)#

#4t - 0 = 19#

#4t = 19#

Step 2) Divide each side of the equation by #color(red)(4)# to solve for #t# while keeping the equation balanced:

#(4t)/color(red)(4) = 19/color(red)(4)#

#(color(red)(cancel(color(black)(4)))t)/cancel(color(red)(4)) = 19/4#

#t = 19/4#