# How do you solve (4x+1)(2x-7) =0?

When you have $a \cdot b = 0$ then $a = 0$ or $b = 0$ hence
$\left(4 x + 1\right) \cdot \left(2 x - 7\right) = 0 \implies 4 x + 1 = 0 \mathmr{and} 2 x - 7 = 0 \implies x = - \frac{1}{4} \mathmr{and} x = \frac{7}{2}$