# How do you solve 4x^2+0.6x=0.54 using the quadratic formula?

Apr 18, 2017

#### Answer:

Get the equation into the correct form first. Then use the quadratic formula to solve.

$x = 0.3 \mathmr{and} - 0.45$

#### Explanation:

$4 {x}^{2} + 0.6 x = 0.54$
$4 {x}^{2} + 0.6 x - 0.54 = 0$

Quadratic formula:
$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

Now plug in...
$x = \frac{- 0.6 \pm \sqrt{{0.6}^{2} - 4 \cdot 4 \cdot - 0.54}}{2 \cdot 4}$
$x = \frac{- 0.6 \pm \sqrt{0.36 + 8.64}}{8}$
$x = \frac{- 0.6 \pm \sqrt{9}}{8}$
$x = \frac{- 0.6 \pm 3}{8}$
$x = \frac{- 0.6 + 3}{8} = 0.3$
$x = \frac{- 0.6 - 3}{8} = - 0.45$

FINAL ANSWER:

$x = 0.3 \mathmr{and} - 0.45$