How do you solve #4x^2+0.6x=0.54# using the quadratic formula?

1 Answer

Answer:

Get the equation into the correct form first. Then use the quadratic formula to solve.

#x=0.3 or -0.45#

Explanation:

#4x^2+0.6x=0.54#
#4x^2+0.6x-0.54=0#

Quadratic formula:
#x=(-b+-sqrt(b^2-4ac))/(2a)#

Now plug in...
#x=(-0.6+-sqrt(0.6^2-4*4*-0.54))/(2*4)#
#x=(-0.6+-sqrt(0.36+8.64))/(8)#
#x=(-0.6+-sqrt(9))/(8)#
#x=(-0.6+-3)/(8)#
#x=(-0.6+3)/(8)=0.3#
#x=(-0.6-3)/(8)=-0.45#

FINAL ANSWER:

#x=0.3 or -0.45#