How do you solve #4x^2 = 12x + 40#?
You could solve this quadratic equation by using the quadratic formula.
For a quadratic equation that has the general form
the quadratic formula takes the form
So, in order to be able to use this formula, get your quadratic to the general form by adding
You can simplify this by dividing all the terms by
The two solutions of the equation will thus be
Ans: -2 and 5.
I use the new Transforming Method. Find 2 numbers knowing sum (-3) and product (-10). Roots have opposite signs.
Factor pairs of (-10) --> (-1, 10)(-2, 5). This sum is 3 = -b.
Then, the 2 real roots are: -2 and 5.