# How do you solve  4x^2 - 5x + 1 = 0 ?

1 and$\frac{1}{4}$
$y = 4 {x}^{2} - 5 x + 1 = 0.$
The 2 real roots are: $1 \mathmr{and} \frac{c}{a} = \frac{1}{4}$