How do you solve #4x^2+5x-6=0# using the quadratic formula?

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Answer 1 · 2016-12-05T23:14:46

#x = 3/4# and #x = -2#

Playing with different factors of #4# and #6# you factor the quadratic to:

#(4x - 3)(x + 2) = 0#

Now solve each term for #0#:

4x - 3 = 0#

#4x - 3 + 3 = 0 + 3#

#4x = 3#

#(4x)/4 = 3/4#

#x = 3/4#

and

#x + 2 = 0#

#x + 2 - 2 = 0 - 2#

#x = -2#