Question

How do you solve `4x^2 + 8x + 3 = 0` using the quadratic formula?

Answer 1

`(-3/2) and (-1/2)`

Explanation:

`y = 4x^2 + 8x + 3 = 0`
Use the improved quadratic formula (Google, Yahoo Search)
`D = d^2 = b^2 - 4ac = 64 - 48 = 16` --> `d = +- 4`
There are 2 real roots:
`x = -b/(2a) +- d/(2a) = -8/8 +- 4/8 = (- 8 +- 4)/8`
`x = -12/8 = - 3/2`
`x = -4/8 = -1/2`