# How do you solve 4x^2 + 8x + 3 = 0 using the quadratic formula?

Apr 15, 2016

$\left(- \frac{3}{2}\right) \mathmr{and} \left(- \frac{1}{2}\right)$

#### Explanation:

$y = 4 {x}^{2} + 8 x + 3 = 0$
$D = {d}^{2} = {b}^{2} - 4 a c = 64 - 48 = 16$ --> $d = \pm 4$
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = - \frac{8}{8} \pm \frac{4}{8} = \frac{- 8 \pm 4}{8}$
$x = - \frac{12}{8} = - \frac{3}{2}$
$x = - \frac{4}{8} = - \frac{1}{2}$