How do you solve $4 x - (2 x + 3) = 7$ $4x-(2x+3)=7$ ?

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How do you solve $4 x - (2 x + 3) = 7$ $4x-(2x+3)=7$ ?

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Answer 1 · 2015-06-12T18:43:58

$x = 5$ $x=5$

Explanation:

Get rid of the bracket changing all the signs inside (because the minus in front of it):
$4 x - 2 x - 3 = 7$ $4x-2x-3=7$
Collect terms with $x$ $x$ on the left and numbers on the right:
$4 x - 2 x = 7 + 3$ $4x-2x=7+3$
add:
$2 x = 10$ $2x=10$
$x = \frac{10}{2} = 5$ $x=10/2=5$

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How do you solve $4 x - (2 x + 3) = 7$ $4x-(2x+3)=7$ ?

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How do you solve $4 x - (2 x + 3) = 7$ $4x-(2x+3)=7$ ?