How do you solve #(4x - 3)^{2} = 36x^{2}#?

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Answer 1 · 2016-09-24T14:19:04

#(4x - 3)^2 - 36x^2 = 0#

Factor as a difference of squares, letting #a = (4x - 3)# and #b = sqrt(36x^2) = 6x#.

#(a + b)(a - b) = 0#

#(4x - 3 + 6x)(4x - 3 - 6x) = 0#

#(10x - 3)(-2x - 3) = 0#

#x = 3/10" AND "-3/2#

Hopefully this helps!