How do you solve #-(4y+1)-(-3y-6)=4#?

1 Answer
Dec 29, 2016

Answer:

#y=1#

Explanation:

#-(4y+1)-(-3y-6)=4#

Keeping in mind that the product of two negatives is a positive and the product of a negative and a positive is a negative, open the brackets and simplify.

#-4y-1+3y+6=4#

#-y+5=4#

Add #y# to each side.

#5=4+y#

Subtract #4# from each side.

#1=y# or #y=1#