How do you solve #4y^2-25=0#?

2 Answers
Apr 12, 2018

Answer:

The answer is going to be #4/5#

Explanation:

How you would do this is adding 25 to the both sides of the equation making the problem #4y^2# = 25. Then you take the square root of 25 and y which will then make the equation look like this 4y = 5. Then just solve for y by dividing 5 by 4 to isolate y and make #4/5# = y or if you want decimal form it would be 0.8 = y

Apr 12, 2018

Answer:

#y=+-5/2#

Explanation:

#"isolate "y^2" on the left side of the equation"#

#"add 25 to both sides"#

#rArr4y^2=25#

#"divide both sides by 4"#

#rArry^2=25/4#

#color(blue)"take the square root of both sides"#

#rArry=+-sqrt(25/4)larrcolor(blue)"note plus or minus"#

#rArry=+-5/2#