Question

How do you solve `4y^2-25=0`?

Answer 1

The answer is going to be `4/5`

Explanation:

How you would do this is adding 25 to the both sides of the equation making the problem `4y^2` = 25. Then you take the square root of 25 and y which will then make the equation look like this 4y = 5. Then just solve for y by dividing 5 by 4 to isolate y and make `4/5` = y or if you want decimal form it would be 0.8 = y

Answer 2

`y=+-5/2`

Explanation:

`"isolate "y^2" on the left side of the equation"`

`"add 25 to both sides"`

`rArr4y^2=25`

`"divide both sides by 4"`

`rArry^2=25/4`

`color(blue)"take the square root of both sides"`

`rArry=+-sqrt(25/4)larrcolor(blue)"note plus or minus"`

`rArry=+-5/2`