# How do you solve 4y^2-25=0?

Apr 12, 2018

The answer is going to be $\frac{4}{5}$

#### Explanation:

How you would do this is adding 25 to the both sides of the equation making the problem $4 {y}^{2}$ = 25. Then you take the square root of 25 and y which will then make the equation look like this 4y = 5. Then just solve for y by dividing 5 by 4 to isolate y and make $\frac{4}{5}$ = y or if you want decimal form it would be 0.8 = y

Apr 12, 2018

$y = \pm \frac{5}{2}$

#### Explanation:

$\text{isolate "y^2" on the left side of the equation}$

$\text{add 25 to both sides}$

$\Rightarrow 4 {y}^{2} = 25$

$\text{divide both sides by 4}$

$\Rightarrow {y}^{2} = \frac{25}{4}$

$\textcolor{b l u e}{\text{take the square root of both sides}}$

$\Rightarrow y = \pm \sqrt{\frac{25}{4}} \leftarrow \textcolor{b l u e}{\text{note plus or minus}}$

$\Rightarrow y = \pm \frac{5}{2}$