How do you solve 4y^2 - 3(y-4)=4y(y-1)+3y?

Apr 23, 2018

When only one variable is there, an equation can be solved by using simplification and $y = 6$ in this equation. You can verify it also by putting $y = 6$ on both sides and the results will be same.

Explanation:

$4 {y}^{2} - 3 \left(y - 4\right) = 4 y \left(y - 1\right) + 3 y$

$4 {y}^{2} - 3 y + 12 = 4 {y}^{2} - 4 y + 3 y \text{ " " } \left[- 3 \cdot \left(- 4\right) = 12 , 4 y \cdot y = 4 {y}^{2}\right]$

or

$4 {y}^{2} - 4 {y}^{2} - 3 y + 12 = - y$

$- 3 y + 12 = - y$

So

$12 = 3 y - y$

$2 y = 12$

$y = \frac{12}{2}$

$y = 6$

Hope it helps...