How do you solve #5/2-x/5=9/10#?

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Answer 1 · 2018-06-22T07:53:34

#x=8#

Simplify the left side first:

#5/2 - x/5# = #((5 xx 5) - (2 xx x))/10# = #(25-2x)/10#

So now we get:

#(25-2x)/10# = #9/10#

Multiply by #10# both sides and we get:

#(10(25-2x))/10 = (9/10)10#

#(cancel10(25-2x))/cancel10 = (9/cancel10)cancel10#

#(25-2x)=9#

-2x = 9-25#

#-2x = -16#

Multiply by #-1# both sides to remove the negative sign

#2x = 16#

#x = 16/2#

#x=8#

Check the answer:

#5/2 - 8/5# = #(25-16)/10# = #9/10# ---> Correct!