How do you solve #5/2t-t=3.3/2t#?

1 Answer
Aug 6, 2017

Answer:

There is either something wrong with the question of #t=0#

Explanation:

Note that #-t# is the same as #-(2t)/2#

Write as:

#(5t)/2-(2t)/2=(3.3t)/2#

As the denominators are all the same write as:

#" "5t-2t=3.3t larr" This is equally true"#

#3t=3.3t#

#0.3t=0" "=>" "t=0#