How do you solve #-5( - 2x + 3) = 15- 5x#?

1 Answer
Sep 8, 2017

Answer:

See a solution process below:

Explanation:

First, expand the terms in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(-5)(-2x + 3) = 15 - 5x#

#(color(red)(-5) xx -2x) + (color(red)(-5) xx 3) = 15 - 5x#

#10x + (-15) = 15 - 5x#

#10x - 15 = 15 - 5x#

Next, add #color(red)(15)# and #color(blue)(5x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#10x + color(blue)(5x) - 15 + color(red)(15) = color(red)(15) + 15 - 5x + color(blue)(5x)#

#(10 + color(blue)(5))x - 0 = 30 - 0#

#15x = 30#

Now, divide each side of the equation by #color(red)(15)# to solve for #x# while keeping the equation balanced:

#(15x)/color(red)(15) = 30/color(red)(15)#

#(color(red)(cancel(color(black)(15)))x)/cancel(color(red)(15)) = 2#

#x = 2#