# How do you solve  5(2x-3)+8=9?

Jun 29, 2018

$x = 1.6$

#### Explanation:

$5 \left(2 x - 3\right) + 8 = 9$

First, subtract $\textcolor{b l u e}{8}$ from both sides of the equation:
$5 \left(2 x - 3\right) + 8 \quad \textcolor{b l u e}{- \quad 8} = 9 \quad \textcolor{b l u e}{- \quad 8}$

$5 \left(2 x - 3\right) = 1$

Now use the distributive property (shown below) to simplify the left hand side:

Following this image, we know that:
$\textcolor{b l u e}{5 \left(2 x - 3\right) = \left(5 \cdot 2 x\right) + \left(5 \cdot - 3\right) = 10 x - 15}$

Put that back into the equation:
$10 x - 15 = 1$

Add $\textcolor{b l u e}{15}$ to both sides:
$10 x - 15 \quad \textcolor{b l u e}{+ \quad 15} = 1 \quad \textcolor{b l u e}{+ \quad 15}$

$10 x = 16$

Divide both sides by $\textcolor{b l u e}{10}$:
$\frac{10 x}{\textcolor{b l u e}{10}} = \frac{16}{\textcolor{b l u e}{10}}$

Therefore,
$x = 1.6$

Hope this helps!