How do you solve #-5+ 2x = 5x - ( 8x + 5)#?

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Answer 1 · 2018-04-07T22:36:20

#x = 0#

Here's how I did it:

#-5+2x = 5x - (8x+5)#

First, we distribute the negative sign to everything in the parenthesis:
#-5+2x = 5x - 8x - 5#

Do #5x-8x#:
#-5 + 2x = -3x - 5#

Add #3x# to both sides of the equation:

#-5 + 2x + color(red)(3x) = -3x + color(red)(3x) - 5#

#-5 + 5x = -5#

Add #5# to both sides of the equation:

#-5 + color(red)5 + 5x = -5 + color(red)5#

#5x = 0#

Divide both sides by #5#:

#(5x)/color(red)5 = 0/color(red)5#

#x = 0#

Hope this helps!