How do you solve #5(2x+6)=-4(-5-2x)+3x#?

2 Answers
Jul 27, 2018

Answer:

#x = 10#

Explanation:

#5(2x+6) = -4(-5-2x) + 3x#

Use the distributive property to simplify/expand:
#10x + 30 = 20 + 8x + 3x#

Simplify the right side:
#10x + 30 = 20 + 11x#

Subtract #color(blue)(11x)# from both sides:
#10x + 30 quadcolor(blue)(-quad11x) = 20 + 11x quadcolor(blue)(-quad11x)#

#-x + 30 = 20#

Subtract #color(blue)30# from both sides:
#-x + 30 quadcolor(blue)(-quad30) = 20 quadcolor(blue)(-quad30)#

#-x = -10#

Divide both sides by #color(blue)(-1)#:
#(-x)/color(blue)(-1) = (-10)/color(blue)(-1)#

Therefore,
#x = 10#

Hope this helps!

Aug 5, 2018

Answer:

#x=10#

Explanation:

We can distribute the #5# on the left and the #-4# on the right to get

#10x+30=8x+20+3x#

Next, we can combine the #x# terms on the right to get

#10x+30=11x+20#

To make it easier, I'll switch the sides. I didn't do any math here, I just switched the sides:

#11x+20=10x+30#

We can subtract #10x# from both sides to get

#x+20=30#

Lastly, to completely isolate #x#, let's subtract #20# from both sides to get

#x=10#

Hope this helps!