How do you solve 5- 4x + 8+ 2x + 3x - 4= 3+ 3\cdot 4?

Apr 17, 2017

See the entire solution process below:

Explanation:

First, group and combine like terms on the left side of the equation:

$- 4 x + 2 x + 3 x + 5 + 8 - 4 = 3 + 3 \cdot 4$

$\left(- 4 + 2 + 3\right) x + \left(5 + 8 - 4\right) = 3 + 3 \cdot 4$

$1 x + 9 = 3 + 3 \cdot 4$

$x + 9 = 3 + 3 \cdot 4$

Next, we simplify the right side of the equation by following the standard rules for the order of operator where you multiply first and then add:

$x + 9 = 3 + \textcolor{red}{3 \cdot 4}$

$x + 9 = 3 + 12$

$x + 9 = 15$

Now, subtract $\textcolor{red}{9}$ from each side of the equation to solve for $x$ while keeping the equation balanced:

$x + 9 - \textcolor{red}{9} = 15 - \textcolor{red}{9}$

$x + 0 = 6$

$x = 6$