How do you solve .5(6^x) = 2^x?

1 Answer
Jan 13, 2016

x=0.631 (3sf)

Explanation:

Take logs of both sides.

log(0.5*(6^x))=log(2^x)

log0.5 + xlog6 = xlog2

log0.5=xlog2-xlog6

log0.5=x(log2-log6)

x=(log0.5)/(log2-log6)

x=log2/(log6-log2)

x=log2/log3

x=0.631 (3sf)