Question

How do you solve `5/6x-2x+4/3=5/3`?

Answer 1

Look, in a way, 2 doesn't mean only 2, it also means `2/1,4/2,6/3,8/4.....` till infinity
Looking in that way,
And also transferring `4/3`
`(5x-12x)/6=5/3-4/3`
Solve
`(-7x)/6=1/3`
Transfer 6 to RHS to multiply `1/3` by 6
`-7x=1/cancel3^1xxcancel6^2`
`-7x=2`
Transfer -7 to RHS, to divide 2 by -7
`x=2/-7`