# How do you solve -5( 8b + 8) = - 160?

Nov 19, 2016

$b = 3$

#### Explanation:

Step 1) Expand the terms within parenthesis:

$\left(- 5 \cdot 8 b\right) + \left(- 5 \cdot 8\right) = - 160$

$- 40 b - 40 = - 160$

Step 2) Solve for $b$ while keeping the equation balanced:

$- 40 b - 40 + 40 = - 160 + 40$

$- 40 b - 0 = - 120$

$- 40 b = - 120$

$\frac{- 40 b}{-} 40 = - \frac{120}{- 40}$

$1 b = 3$

$b = 3$