How do you solve #5^(-9.2x-9)-4=57#?

1 Answer
Nov 18, 2016

Answer:

Isolate the term involving the variable, then take the #log_5# of both sides.

Explanation:

#5^(-9.2x-9)-4=57#

#5^(-9.2x-9)=61#

#log_5(5^(-9.2x-9))=log_5 61#

#-9.2x-9=log_5 61#

#-9.2x=log_5 61+9#

#x=-(log_5 61+9)/9.2#

#(xapprox-1.2559)#