How do you solve #5( a - 7) = 30#?

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Answer 1 · 2017-04-24T19:03:57

#a=13#

Order of operations.
Multiplication first. #color(red)(5(a-7))#

#5(a-7)=30#

#5a-35=30#

Move #-35# to the other site of the equals sign so we can have #5a# alone

#5a=30+35#

#5a=65#

Now divide both sides by #5# to find the value of #a#

#(cancel5a)/cancel5=65/5#

#a=13#

Always check your answer if you are not sure

Since #a=13#,

#5(a-7)=30#

#5((13)-7)=30#

#5(6)=30#

#30=30#