# How do you solve #(5\cdot 3\cdot 2) \div ( 6+ 3\cdot - 1+ 2)#?

##### 2 Answers

#### Explanation:

In any expression involving different operations, count the number of terms first.

Each term will simplify to a single answer and these are added or subtracted in the last step

Within each term, the normal order of operation applies.

**Brackets** first, then work from the strongest to weakest operations :

**powers and roots**

then **multiply and divide**

**add and subtract** LAST

=

=

=

6

#### Explanation:

We deal with the mixed operations in this calculation in the order set out in the acronym PEMDAS.

That is by evaluating brackets first.

#(5xx3xx2)÷(6+color(red)(3xx(-1))+2)#

#=30÷(6color(red)(-3)+2)larr"multiplication before addition"#

#=30÷5=6#