How do you solve #(5\cdot 3\cdot 2) \div ( 6+ 3\cdot - 1+ 2)#?

2 Answers
Sep 22, 2016

Answer:

#6#

Explanation:

In any expression involving different operations, count the number of terms first.

Each term will simplify to a single answer and these are added or subtracted in the last step

Within each term, the normal order of operation applies.

Brackets first, then work from the strongest to weakest operations :
powers and roots
then multiply and divide

add and subtract LAST

#(color(red)(5xx 3xx 2))div ( 6+ color(blue)(3xx (- 1)) + 2)" "larr# there is only 1 term

=#(color(red)(30))div ( 6 color(blue)(-3) + 2)#

= #30 div 5#

=#" "6#

Sep 22, 2016

Answer:

6

Explanation:

We deal with the mixed operations in this calculation in the order set out in the acronym PEMDAS.

That is by evaluating brackets first.

#(5xx3xx2)÷(6+color(red)(3xx(-1))+2)#

#=30÷(6color(red)(-3)+2)larr"multiplication before addition"#

#=30÷5=6#