# How do you solve 5(x-3)^2 = 45?

Apr 21, 2018

$x = 6 \mathmr{and} x = 0$

#### Explanation:

Divide both sides by 5

$\implies$ ${\left(x - 3\right)}^{2} = 9$

Square root both sides

$\implies$ $x - 3 = \setminus \pm 3$

$\implies$ $x = 6 \mathmr{and} x = 0$