Question

How do you solve 5(x+3)=7#?

Answer 1

`x=-8/5`

Explanation:

distribute the bracket on the left side of the equation.

`rArr5x+15=7`

Isolate 5x by subtracting 15 from both sides of the equation.

`5xcancel(+15)cancel(-15)=7-15`

`rArr5x=-8`

To solve for x, divide both sides by 5

`(cancel(5) x)/cancel(5)=(-8)/5`

`rArrx=-8/5`

`color(blue)"As a check"`

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

`5(color(red)(-8/5)+3)=cancel(5)^1xx-8/cancel(5)^1+(5xx3)=-8+15=7`

`rArrx=-8/5" is the solution"`