How do you solve #5(x + 4) = 10#?

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Answer 1 · 2016-04-05T13:08:29

#x=-2#

#color(blue)(5(x+4)=10#

Use distributive property

#color(brown)(a(b+c)=ab+ac#

#rarr5x+20=10#

Subtract both sides by #20#

#rarr5x+20-20=10-20#

#rarr5x=-10#

Divide both sides by #5#

#rarr(cancel5^1x)/cancel5^1=-10/5#

#color(green)(rArrx=-2#

Check

#5(-2+4)=10#

#5(2)=10#

#10=10#

Correct!