# How do you solve #5/(y-3) - 30/(y^2-9)= 1#?

##### 1 Answer

May 15, 2015

5y + 15 - 30 = (y - 3)(y + 3)

5(y - 3) = (y - 3)(y + 3) -> 5 = y + 3 -> y = 2.

May 15, 2015

5y + 15 - 30 = (y - 3)(y + 3)

5(y - 3) = (y - 3)(y + 3) -> 5 = y + 3 -> y = 2.

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