Question

How do you solve `5/(y-3) - 30/(y^2-9)= 1`?

Answer 1

`[(5(y + 3))/(y^2 - 9) ] - 30/(y^2 - 9) = 1`

5y + 15 - 30 = (y - 3)(y + 3)

5(y - 3) = (y - 3)(y + 3) -> 5 = y + 3 -> y = 2.