How do you solve $50w \div ( 90+ w ) = 20$ ?

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Answer 1 · 2018-01-15T13:38:49

See a solution process below:

First, rewrite the expression as:

$(50w)/(90 + w) = 20$

Next, multiply each side of the equation by $color(red)((90 + w))$ to eliminate the fraction while keeping the equation balanced:

$color(red)((90 + w)) xx (50w)/(90 + w) = color(red)((90 + w)) xx 20$

$cancel(color(red)((90 + w))) xx (50w)/color(red)(cancel(color(black)(90 + w))) = color(red)(90 xx 20) + (w xx 20)$

$50w = 1800 + 20w$

Then, subtract $color(red)(20w)$ from each side of the equation to isolate the $w$ term while keeping the equation balanced:

$50w - color(red)(20w) = 1800 + 20w - color(red)(20w)$

$(50 - color(red)(20))w = 1800 + 0$

$30w = 1800$

Now, divide each side of the equation by $color(red)(30)$ to solve for $w$ while keeping the equation balanced:

$(30w)/color(red)(30) = 1800/color(red)(30)$

$(color(red)(cancel(color(black)(30)))w)/cancel(color(red)(30)) = 60$

$w = 60$

How do you solve 50w \div ( 90+ w ) = 2050w \div ( 90+ w ) = 20?