# How do you solve 5abs(2x + 1 ) = 55?

Mar 16, 2018

$x = - 6 , 5$

#### Explanation:

We got: $5 | 2 x + 1 | = 55$

Dividing both sides by $5$, we get

$| 2 x + 1 | = \frac{55}{5}$

$= 11$

So, $2 x + 1 = \pm 11$, since $| a | = \pm a$.

And so,

$2 x + 1 = 11$

$2 x = 10$

$x = \frac{10}{2} = 5$

$2 x + 1 = - 11$

$2 x = - 12$

$x = - \frac{12}{2} = - 6$

As you can see, there are two solutions for $x$, and $x \setminus \in \left\{- 6 , 5\right\}$.