# How do you solve  5b + 2 = 17?

Jul 27, 2015

$b = 3$

#### Explanation:

We will group the numbers with each other and leave the the variable $b$ alone on one side of the equation.

This means that you will have $+ 2$ to be next to the 17, but because the 17 is on the other side of the equation, $+ 2$ will become $- 2$.

$5 b = 17 - 2$

$5 b = 15$

Therefore,

$b = \frac{15}{5}$

now divide both sides of the equation by $5$ to get

$\frac{\cancel{5} \cdot b}{\cancel{5}} = \frac{15}{5}$

$b = 3$