×

# How do you solve 5e^(2x+11)=30?

Jan 27, 2016

I found $x = - 4.6$

#### Explanation:

We can rearrange it as:
${e}^{2 x + 11} = \frac{30}{5}$
${e}^{2 x + 11} = 6$
take the natural log of both sides:
$\ln {e}^{2 x + 11} = \ln 6$
giving:
$2 x + 11 = \ln 6$
$2 x = \ln 6 - 11$
$x = \frac{\ln 6 - 11}{2} = - 4.6$