How do you solve $5 e^{2 x + 11} = 30$ $5e^(2x+11)=30$ ?

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How do you solve $5 e^{2 x + 11} = 30$ $5e^(2x+11)=30$ ?

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Answer 1 · 2016-01-27T00:12:15

I found $x = - 4.6$ $x=-4.6$

Explanation:

We can rearrange it as:
$e^{2 x + 11} = \frac{30}{5}$ $e^(2x+11)=30/5$
$e^{2 x + 11} = 6$ $e^(2x+11)=6$
take the natural log of both sides:
${ln e}^{2 x + 11} = ln 6$ $lne^(2x+11)=ln6$
giving:
$2 x + 11 = ln 6$ $2x+11=ln6$
$2 x = ln 6 - 11$ $2x=ln6-11$
$x = \frac{ln 6 - 11}{2} = - 4.6$ $x=(ln6-11)/2=-4.6$

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How do you solve $5 e^{2 x + 11} = 30$ $5e^(2x+11)=30$ ?

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How do you solve 5e^(2x+11)=305e2x+11=305e^(2x+11)=30?

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How do you solve $5 e^{2 x + 11} = 30$ $5e^(2x+11)=30$ ?