How do you solve #5e^(2x+11)=30#?

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Gió Share
Jan 27, 2016

Answer:

I found #x=-4.6#

Explanation:

We can rearrange it as:
#e^(2x+11)=30/5#
#e^(2x+11)=6#
take the natural log of both sides:
#lne^(2x+11)=ln6#
giving:
#2x+11=ln6#
#2x=ln6-11#
#x=(ln6-11)/2=-4.6#

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