How do you solve $5ln x = 35$ ?

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Answer 1 · 2015-12-21T04:49:51

$x=e^7$

Divide both sides by $5$ .

$lnx=7$

Undo the natural logarithm by exponentiating both sides.

$e^(lnx)=e^7$

$x=e^7$

This could also be solved by rewriting $5lnx$ using logarithm rules.

$ln(x^5)=35$

$e^(ln(x^5))=e^35$

$x^5=e^35$

$(x^5)^(1/5)=(e^35)^(1/5)$

$x=e^7$

How do you solve 5ln x = 355ln x = 35?