How do you solve $- 5 m - 2 - 3 (m - 1) = 3 m - (8 m - 2) - 7 m + 7$ $-5m - 2- 3( m - 1) = 3m - ( 8m - 2) - 7m + 7$ ?

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Answer 1 · 2018-04-30T18:28:58

The answer $m = 4$ $m=4$

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$- 5 m - 2 - 3 (m - 1) = 3 m - (8 m - 2) - 7 m + 7$ $-5m - 2- 3( m - 1) = 3m - ( 8m - 2) - 7m + 7$

$- 5 m - 2 - 3 m + 3 = 3 m - 8 m + 2 - 7 m + 7$ $-5m-2-3m+3=3m-8m+2-7m+7$

$- 8 m + 1 = - 12 m + 9$ $-8m+1=-12m+9$

$4 m = 8$ $4m=8$

$m = 4$ $m=4$

How do you solve -5m - 2- 3( m - 1) = 3m - ( 8m - 2) - 7m + 7−5m−2−3(m−1)=3m−(8m−2)−7m+7-5m - 2- 3( m - 1) = 3m - ( 8m - 2) - 7m + 7?